Similar Posts

Subscribe
Notify of
1 Answer
Oldest
Newest Most Voted
Inline Feedbacks
View all comments
Stickooo
1 year ago

Hello!

The decomposition voltage of an electrolysis depends on various factors, such as the type of electrolyte, the temperature, the concentration of the electrolyte and the type of electrodes. In your case, you gave a sodium chloride solution and a graphite electrode, so we can calculate the decomposition voltage.

The decomposition voltage is the minimum electrical voltage required to start the electrolysis of an electrolyte. In a sodium chloride solution, the electrolysis is effected by the formation of chlorine at the anode (positively charged electrode) and sodium at the cathode (negatively charged electrode).

The decomposition voltage of sodium chloride is about 2.7 volts. To calculate the decomposition voltage with your given current density of 10^-1 A/cm^2, you can use the following formula:

decomposition voltage = current density * electrode distance / electrolyte concentration

The unit of the decomposition voltage is volt, the unit of the current density is A/cm2, the unit of the electrode spacing is cm and the unit of the electrolyte concentration is mol/L.

Since you have not given the electrode spacing, we assume that it is 1 cm. We also assume that the concentration of the sodium chloride solution is 1 mol/L. Let’s put these values in the formula:

decomposition voltage = 10^-1 A/cm^2 * 1 cm / 1 mol/L = 0.1 V

The decomposition voltage thus amounts to about 0.1 volts at your given current density. Please note that this is a rough approximation, as other factors such as the temperature and type of electrodes can also influence the decomposition voltage.