Hey, I'm supposed to present the following problem in physics class on Monday. Unfortunately, I'm having a hard time with this problem and don't know what steps I need to take to solve it. I hope someone can help me! Thanks in advance!
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Loading...The hour hand of a tower clock (hand length = 1.25 m) is permanently connected to a gear (z = 96 teeth). This gear is driven by a gear Z2 with 32 teeth. What is the average angular velocity of Z2? The result is 0.025 °/s The calculation would be: ( 2 * 360° /…
Could someone please help me with the tasks! On the B58, a turning bus failed to see a truck. The driver braked hard, causing a pipe to shoot through the driver's cab from behind (>Fig. 7). a) From the truck driver's perspective, the pipe was accelerating forward. According to the basic equations of mechanics, this…
Hello, I'm graduating from high school this year. I'm considering studying physics afterward, as math seems far too theory-heavy for me, and I see more application in physics. Ideally, I'd like to go into research and possibly even go abroad. However, I didn't have physics in high school; the last time I had physics was…
Could someone maybe help me name these molecules? Thanks in advance 🙂
What is convection in physics? Could you please explain it briefly but clearly? Best regards
I just put warm water in these ice cube trays in the freezer. I hope it turns into ice.
In the first diagram, you can see the location as a function of time, in the second the height as a function of time and in the third you have a side view of the throwing path. You can easily calculate the speed from the first diagram using the formula v=s/t or v= Δx/Δt. As if you are to read the slope of a function in math class. Then you simply search for some area where you can read the two values very nicely, for example at 0.5s and at 2 meters. The starting point and time are zero. This means: Δx=x(speed 2) -x (starting speed)=2 meters – 0 meters = 2 meters. Δt=t(time point 2) – t(Start)=0.5s – 0s=0.5s. If this is now put into the formula for the speed, 4m/s are obtained and thus have task a. For task b, you simply use the second diagram and see at which y it is 1.5s at the time and then see where the y value is in the third diagram, then you have the place at the height/y value 1.5s at the same time
The movement can be divided into two independent partial movements.
Horizontal: 1. Chart. t-x is a time-way diagram. The speed is in the gradient. Since it is a straight line, you can say something important about the value of speed.
Vertical: 2nd diagram. It shows the free fall. What movement is that?