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CliffBaxter
1 year ago

now, it must be taken into account that the O2, which is ejected, originates not from the CO2, but from the splitting of water.

And to push out 6 O2, not enough 6 H2O left. You need 12 H2O. Therefore, these 12 H2O must also appear left in the equation and 6 of them – formal – also right.

This equation was simplified by deducting -6 H2O on both sides, which Rolf said:

6 CO2 + 6 H2O → C6H12O6 + 6 O2

Thus it stands in many school books, as a simplified equation, but then suggests that the oxygen originates from the CO2. What is not the case now. The water on the right is nice when all primary and secondary reactions are included.

Therefore, your equation is the correct form. LG

kirk2021
1 year ago

Strike the 6 H2O back, then it should be right

Rolf42
1 year ago
Reply to  kirk2021

No, then the equation is no longer correct. One would have to remove 6 H2O on both sides so that the sum is correct.

But I don’t know whether the reaction would actually take place.

kirk2021
1 year ago
Reply to  Rolf42

Joa, or something. At any rate no water comes out at the back