How many liters are consumed during an acceleration process?
Hello, my problem is: How much energy is needed to accelerate a car with a mass of 1.11 tons to a speed of 55 km/h? The answer is relatively simple: 128.38 J. However, I don't understand the question: if the engine's efficiency is 27% and the calorific value of gasoline is 2.6⋅10 J/liter, how many liters of gasoline are consumed during one acceleration cycle? Does anyone have any idea how to arrive at this result?
LG
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That may be simple, but it’s also wrong. With E=1⁄2mv2 I get 130 kJ.
What do you mean? If I google after the calorific value of petrol, then I find values of the order of 3.2⋅107 J/l. So I assume that you should have 2.6⋅107 J/l. But I do not take a guarantee that I have properly completed this text of the gap.
With this information, however, I can at least further calculate. Of these 2.6⋅107 J/l, the engine can convert 27% to 7.02⋅106 J/l, which is 7020 kJ per liter of fuel.
But we only need 130 kJ, that is the 130⁄7020 or 1.8% of this amount of energy, so we need only 1.8% of one liter of fuel, that is 18 ml.
Calculation error: 27% so 7.02⋅106 J/l
Oh, fyck, you’re right, that’ll be corrected. But it was only a one-time typing error that I think is correct.
The next bill is true! Thank you very much!! 🙂
The mechanical, physical work by the acceleration is ultimately the energy that is contained in the vehicle. This is the kinetic energy. Please check your account again… apropos… do the points in the numerical values mean comata or points?
for efficiency. If the efficiency is not 100 percent in the case of an energy transformation, then you have to apply more than behind it. If the Wg is 50% you have to 1/0.5. use more than you have after. At 27% it is 1/O.27 times more….
Three-set calculation.
Calculate how much liter it would be at 100% efficiency, and then convert it to 27%.