Why is the location factor irrelevant for spring pendulums?
Hello,
Today in physics, we learned that a spring pendulum oscillates the same way for any position factor. That's why astronauts use a spring pendulum to weigh themselves.
Now my question is why this is so, since FG is an additional force that "pulls" the object on the spring. Therefore, the amplitude "upward" should be smaller than the "downward" amplitude, precisely because a force is pulling the object downward. Why does the force apparently have no effect on the object?
Thanks
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apparently a communication problem (not properly explained or not properly listened) – the deflections are different, only the frequency is equal.
When more force pulls downward on the object, the spring is deflected further, which results in a greater spring force in the opposite direction, so that the spring also swings further upwards, i.e. with greater deflection. Energy conservation also presupposes. If the feather would swing further down than energy would have vanished upwards (free of friction, of course).
This is inappropriate. Both the frequency and the vibrational inlay are influenced by the local gravity acceleration when it acts in the direction of oscillation.
The gravitation has an impact on the Restoration the mass hanging on the pendulum, i.e. on the expansion of the spring in the idle state.
However, it has no effect on Vibration; This depends only on the properties of the spring and on the mass hanging thereon.
If, for example, a gravity force holds a spring rocker in a rest position, the frequency is 0, you suddenly remove the gravity effect, the rocker begins to oscillate. Thus, each change in the position of the location will also influence the oscillating process. Even the vibrations of atoms are influenced by the location or by the position in the acceleration field.