The graph of a completely rational function of degree 3 intersects the y-axis at -1; the tangent at this intersection point is the y-axis. The graph also has the lowest point 0 / -1
I know I have 4 conditions but I only have 3 points?
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Loading...in a.) (80.5%) I get the right result, but in b.) not
I'm not getting anywhere with this at all. It's about task 10, part B, subsections 1 and 2. Thank you very much
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Hey people, I'm practicing math but I'm stuck on the last two tasks (the first one isn't so bad, focus on the last one) I don't understand why there's suddenly a 6 there, etc. can someone explain this to me?
In fact, it was a calculator she called up on her phone and had nothing to do with the cash register system. I was right next to her. She's made a few mistakes on simple calculations and now uses the calculator almost all the time…I think she's only 18.
Cuts the y axis DIESELBE condition like TP at (0/-1)
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You don’t have four conditions, you’re buzzing four.
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f(0) = -1
f'(0) = 0
lean ZWEI conditions
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“The tangent at this point of intersection is the Y axis.” There are no vertical tangents at allrational Fkt .
For
This is not a function since the tangent runs on Y.
What do I have to do?
I don’t know
The y-axis can be used for an integer function
not being tangent.
What do I do with the info
Should the last point be (0 | 1) or (0 | -1)?
In the first case, there was nothing left.
Ups my mistake must be 0/-1