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Halbrecht
11 months ago

above stands x^8 , below stands x^7 . What remains above?

.

also y stays up (high (8-7) )

.

also z

now short 7 28 and 5 25

gauss58
11 months ago

^m * a^n = a^(m + n)

a^m / a^n = a^(m – n)

sarah3
11 months ago

Shorten 7 against 28, 5 against 25, x^8 against x^7,

y high 8 against y high 7, z high 4 against u high 3

Note by definition (x,y and z must not be zero)

Vampirjaeger
11 months ago

You can simply shorten, e.g. with x^2 in the left part. Then x^2 remains below.

RipedimeActing
11 months ago

Put everything in a break. You will then cut it from 7*5*x^8*y^8*z^4 / 25*28*x7*y^7*z^3 to 1*1*y^1*z^1 / 5*4*x^0*y^0*z^0 =xyz/20.

I hope that was quite understandable now.

Lg RipedimeActing