How should I imagine the difference between high-energy and low-energy bonds?

I imagine it like this:

Example using single bond and double bond:

Double bonds are stronger than single bonds.

Stronger and more stable means lower energy. Low energy means you have to put in a lot of energy to break the bond.

Do I have to imagine that in order to break bonds the sum of the energy INSIDE the bond before breaking and the energy supplied from outside to break it is ALWAYS THE SAME and that is why the energy supplied is always greater for more stable or lower energy bonds than for higher energy bonds because they require more energy from outside to reach the above-mentioned sum, which is always the same?

I bet my thought is wrong.

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JenerDerBleibt
1 year ago

You like to say that with energy and low because you can imagine it well. There.ss in the bond itself is literally energy, but is not quite right. The problem is that you can’t really imagine what happens in subatomic space.

I’m trying to paint a picture. Imagine a ball lying on a level. This is an unbound atom. If there’s a bond now, the ball rolls into a valley. As a result, it obtains motion energy which is set free (this is the energy which is released during the binding operation) and remains below. If you want to break the binding, you have to roll up the ball again. Of course, it costs energy.

With a low-energy bond, this valley is now deeper than with an energy-rich one. Ergo can release more energy when a low-energy bond is coupled. But that is why there is no energy in the energy-rich bond.

JenerDerBleibt
1 year ago
Reply to  Hellasisgood

Exactly

JenerDerBleibt
1 year ago

Yes in principle

JenerDerBleibt
1 year ago

Oh, that’s probably just supposed to explain what bond is split. This has no particular chemical significance.

JenerDerBleibt
1 year ago

What do you mean with snake lines? Do you have a picture of it?