Wie löse ich folgende Physikaufgabe?

Eine Wäscheschleuder von 56 cm Durchmesser dreht sich dreißigmal pro Sekunde. Bestimmen sie den Betrag der Zentripetalbeschleunigung an der Trommelwand sowie den Betrag der Kraft, mit der dort ein Wasserteilchen (m=1g) vom Stoffgewebe festgehalten werden müsste, um nicht fortzufliegen.

Danke im Voraus 🙂

(No Ratings Yet)
Loading...

Similar Posts

Subscribe
Notify of
1 Answer
Oldest
Newest Most Voted
Inline Feedbacks
View all comments
ProfFrink
1 year ago

Look at your physics book. As a rule, there are two formulas for calculating the centripetal acceleration.

or

Both formulas lead to the same result, although the radius is once in the counter and the other time in the denominator. If you like to recreate at angular speeds, consider that it is calculated in the unit RAD/sec. A full rotation then corresponds to the angle of 2*pi. The circumferential speed, on the other hand, is set with the unit m/s if you want an acceleration in the unit m/s2 at the end.

In the end you shall calculate a force. Going with the relationship

Force = mass * acceleration

But consider that the unit Newton refers to 1 kg and not to 1 g.