How do I solve this problem?
I don't understand how to draw the rays.
(1 votes)
Loading...Similar Posts
Determine the unit of the Boltzmann constant?
Dear community, it would be great if someone could explain the first problem to me, or maybe all of them. I'm new to this course and haven't studied much physics in school. I'm having particular trouble getting to grips with the topic of units. I think another example would definitely help me develop a better…
BMW M550i G30?
I have a few questions about a conversion My friend's m550i currently has the right headlights installed. Would it be possible to install the left headlights plug in play? In addition, I don't think it has a very nice speedometer inside Would it be possible to convert it to a fully digital speedometer? Are there…
Kick in a car window?
Kicking in a car's side window with your foot? Is that possible? For example, when a baby is sitting inside crying in 35-degree heat? Whether it's technically possible, not legally.
Physics units?
Hey guys, I have a physics test tomorrow.. Unfortunately I'm still confused about all the units (micro, milli, kilo and so on). Whenever the task says to convert 1 kilo to micro, for example, do you have to add 6 zeros or however many?😬 I can't do any of that..
Moped lights not working properly?
Good evening everyone, My question concerns my 50cc moped. It's a Yamasaki Ym50-9, and I have the following questions. 1. Only the left headlight lights up, both in low beam and high beam. Even though there's also a bulb in the right headlight. Is that correct? 2. When I use the front brake, the brake…
If it's not a satellite, then what is it?
The object is stationary and appears as distant as stars and shines like the moon. The first thought of the people I asked was that it was a satellite, only satellites move. This one was stationary; it's definitely not a star and therefore not a satellite. What else could it be? (The first is the…
If Tom Mia can see in the mirror or vice versa (it is either both the case or none of both), Tom can see the mirror image of Mia when you touch the mirror as a window, and also the mirror image of Tom Mia can see.
The mirror image of at least one of the points at the level of the mirror is thus constructed for the beam path. We have a projection on the floor level, so you can mirror the straight line (in the plane of the drawing) which is defined by the mirror. This is almost the line that represents the wall at the lower edge of the picture. (It is probably thought that you take this wall as a mirror straight – if you want to take it quite accurately, you can also take the straight through the mirror that is a few millimeters higher.)
Design the mirror image M’ of M (the place where Mia is right).
Connect T (the place where Tom is straight) with M′. From T to S (mirror) the line is usually drawn through, from S to M′ usually dashed.
When the connecting line goes through the mirror, Tom Mia can see.
From S to M you can get in one of 2 ways:
Examples of such sketches can be found, for example https://www.google.com/search?q=construction+spiegelbild&tbm=isch
I have to correct it again
Okay, so with a mirror, the angle of incidence of the light is= Angle of light, so you take a geographic triangle and see at which point of the mirror the line to Tom would have the same angle to the mirror plane as seen from the same point the line to Mia. The 2 line determined in this way are the sought light beam.
Since Mia and Tom are accepted as points, there is also no wide viewing area, but only this one (sight) beam reflected by the mirror.