How do you solve task 1?

Aaaaaa.

We have the straight line. The straight g is an infinitely long straight line in the middle of the area.

The mathematicians need a fat formula to describe it.

First comes the name g, which is so that one can distinguish g from other straight lines.

Then the support vector comes:

(1)

(1)

(2)

This is the path from point (0/0/0), i.e. the origin in the coordinate system to point (1/1/2). The point is simply on the straight line. This is the one-off task of the support vector. Just be a way to some point on the straight line. In the future, if you have a point on a straight line that packs so vertically in vector writing and zack, you have a support vector.

Then come on

….(0)

+t • (-2)

….(7)

This is the insurance for the straight also really going in one direction. For the support vector fu now goes -2 in the y-direction and 7 in the z-direction. And the t-time. If t is 1000, you go 1000 times in the direction. t is the parameter and the vertical (0/-2/7) is called direction vector. Imagine the support vector is the road from a house on the edge of the city to the “main road” and the main road is then the actual straight line. The main road then shows in the direction of the direction vector.

For the points -2, 1 and 3 you simply enter them for t and calculate this. For -2

….(1) ……….(0) …(1) …(1)

x= (1) + (-2)* (-2) = (1) + (4) = (5)

….(2)………… (7) …(2) ..(-14)(-12)

The point is therefore P(1/5/-12). You can do the rest yourself, you know better. b) I have already explained to you

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