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DerRoll
6 months ago

If you have already proved that the a_n is strictly monotonically falling, it is enough to prove that the a_0 <= 2 is to show that the 2 must be an upper barrier (why?). a_n - 1 = 1/n > 0, i.e. all a_n > 1 and thus 1 is a lower limit for a_n.

DerRoll
6 months ago
Reply to  Leasforlive

Look, I’m staying with you. If you don’t understand, you should consider choosing the right subject for you. You are not even able to formulate your problems and difficulties of understanding independently. That’s never gonna happen.

Mathematics is now at this level formula language, there is no way to go.

DerRoll
6 months ago

If you think it’s really nasty when I tell you that you obviously lack essential foundations then that’s the way. I must live with that.

DerRoll
6 months ago

I can’t do that. I can’t explain it better.

DerRoll
6 months ago

I wrote you how to get to the 1st.

DerRoll
6 months ago

I can’t explain it better. You obviously lack all the basics, I’m sure I won’t start from the front.

Pseud000
6 months ago

Naja, 1> 1/n >0 for all n and hence 2 = 1 + 1 > 1 + 1/n > 1 + 0 = 1