Good afternoon, dear math community!
I'm asking for your help with an example, as I can't seem to find any clue as to how to approach this. I hope someone can help me.
Thank you in advance ^_^
(1 votes)
Loading...Hello, I have the following task Median 0 and 7, mean 1.62 and 6.35 How do I calculate the upper and lower quartile? Thank you!
Please solve subtask b Thanks for the help
Here, the gtr was used for the result of task a3. How exactly do you get that, and what do you have to enter? Thanks in advance.
Could someone explain the tasks to me VERY simply? Unfortunately, I don't understand them at all.
Hello, I just did number a) of this task. Can someone quickly check if my results are correct, because there is no solution… Thanks for help!
No.2 b and c; a) I have already processed myself
a(1) = 2
a(2) indicate the distance lying at the top of the hatched triangle, it is as long as half the base of this triangle, so according to Pythagoras
a(2) = 1/2 * Root(2 a(1)^2) = a(1) / Root(2)
General
a(n+1) = a(n) / root(2), or
a(n) = 2 / Root(2)(n-1)
The sum a(1) + a(2) + … then gives the geometric row
2 * Sum(n=0, infinite, 1 / Root(2)^n )
You should get that with the areas now.
Entrance:
The triangles are at right angles.
The first triangle has the Kathete a_1 and the hypotenuse h_1 = a_1 * √2 (Pythagoras).
The hypotenuse h_1 is the catheter a_2 of the second triangle. Hypotenuse h_2 = 2 * a_1 (Pythagoras).
The hypotenuse h_2 is the catheter a_3 of the third triangle. Hypotenuse h_3 = 2 * a_1 * √2.
etc.
The adjacent lengths a_i differ in each case by the factor √2.
With this knowledge you should be able to solve the task.
Thank you very much. Have a good day. ☺️