What are the partial equations for ion formation (chemistry)?

monikaa1907Bymonikaa1907

Heyy,

I've been given a chemistry homework assignment where I'm supposed to work out the partial equations for the ion formation of antimony(V) oxide. However, I don't really understand the topic and don't know how to do it.

I already spoke to the teacher and she explained the topic to me again, but I still didn't understand it.

I don't know if it's the way she explains it or if I'm just stupid.

Could someone please briefly explain it to me and tell me how to do it? I absolutely have to do the homework because the teacher is very strict about homework.

thanks in advance

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JenerDerBleibt
JenerDerBleibt
11 months ago

I guess you just haven’t been through yet. In principle, this is quite simple. The name antimony(V) oxide already reveals the oxidation level of antimony. So we have Sb^5+ ions here. Oxygen has, as is known, 2- as charge in the ionic state. Thus one writes in the partial equations:

Oxidation: Sb -> Sb^5+ + 5 e^-

Reduction: O2 + 4 e^- -> 2 O^2

And then all:

4 Sb + 5 O2 -> 2 Sb2O5

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