How do I determine the zeros?
How do I determine the zeros of the function e^x-4x
Could someone show me this step by step, as I can't figure it out myself.
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Why is cos(2-x) shifted by 2 to the right and not to the left?
Because normally the positive values indicate a shift in the negative direction and vice versa….
Integral calculations?
Can someone please explain this calculation method to me in detail, I don't understand the second step in particular
Quadratic equation?
ByErinuu69
Does it matter if, in my solution, for example, X1=7 and X2=9, or if I do X1=9 and X2=7, would it make any difference?
exp(4x)=4x has no intersection, so there is no zero. You can quickly see that when you enter the functions in a coordinate system.
only e^x, not e^4x
Oh, right. Then there are zero places
By “normal” calculations as usual: not at all
.
You can find the starting value for an approximation solution with the intersection of e^x and -4x
There is no step-by-step solution because the solution only goes with the Lambert W function that is not a school material.
see also: https://www.wolframalpha.com/input?i=e%5Ex-4x%3D0
Numeric solution or GTR is recommended.
GeoGebra: