Bymxwc8
I really don't understand how to calculate the differential quotient for exercises 1a and 1b. I don't even know where to start. I have no idea if the formula…
lim h→∞ f(x+h)-f(x)/h
…is actually the right one for it.
Can anyone help me?
(1 votes)
Loading...With the number "a" I don't know what to do, I know how to do it but the fact that it says 2 times x squared without a minus confuses me
Only syntax errors or per square root number come out. The result must be 13
No matter what I do, I always get 11, but never 19.57. Why is that? And is the circuit inductive or capacitive?
For a short story, I want to fake an ISBN, the numbers of which are supposed to be a hidden reference to Langlands. Unfortunately, negative numbers aren't possible, otherwise I would have thought of this: https://oeis.org/A002070 Do you have any ideas?
Yes, due formula is right.
If what’s under the task of you, you’ve done a lot of things very well. a) is finished because due function is a straight line.
At b), you must now not form the lime for h to zero, just as xey is in the formula. Then you have 2×0 +h and h goes against zero. Thus your gradient at x0 is equal to 2×0.
Is it concrete?
NO!!!! Specifically: h goes against zero. In mathematics, nix falls away.
You can sometimes shorten or subtract something or as here, something goes against zero.
In none of the cases, it falls away.