ByBoxer05
Hello
I need a 9-turn coil with 0.5mm wire. Unfortunately, I only have 0.65mm steel wire. Does this make a difference, and if so, what do I need to change to use this wire?
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The inductance depends purely on the diameter of the windings and their number.
If you use thicker wire, the diameter of the winding is of course somewhat larger when you wrap it on the same coil body. The difference is minimal.
However, if you have several layers, the coil will of course “thicker” and the average of the winding diameter will then be significantly larger. The more layers, the more the effect.
But what changes greatly is the ohmic resistance. The thicker or more conductive the wire, the less ohm the coil then has. Since steel leads less than copper, you even need a thicker wire to get the same ohm number.
Whether you can use the steel wire depends on the application, so how sensitive the circuit reacts to another ohmic resistance. Most of the time, it is not desired. A better and thicker wire is then advantageous here. In your case, it is difficult to say whether the number of ohms goes up or down as you use a worse but thicker material.
The wire is only thicker it should definitely be used steel wire. I need the coil for a low frequency filter
If they prescribe the exact material, the ohmic resistance will also play a role. And this is clearly different with thicker wire.
On the other hand, 9 turns are not much and the length of the “connection legs” also plays a major role. If you make them longer, you automatically get more ohms into the system.
With self-made coils, the way you wrap plays a very big role, so “sensitive” cannot be the circuit.
If the wire is not insulated, you can easily stretch it. Wire is drawn to the desired diameter. So, if you pull tight, it won’t only be longer, it will also be thinner. So you could get that on the 0.5 with a little Try&Error.
Magnetic field is different and the current will be higher.
The wire is not so much thicker and steel is much worse than copper. I think the current will be smaller – at least with direct current.