Why is it so: implication f=>w <=>w?
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Can it be that there are no brackets? What exactly is that? From f follows w is also when true when both f and w are wrong. The equivalence (f -> w) <=> w is therefore not given.
Error of me, it must be so: (f->w)->w
The implication has the property only to be wrong if the premise is true and the consequence is wrong. That is, if f and w are wrong, f -> w is true but (f->w) -> w is wrong, so this chain also falls on the nose.
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