Why does the series of alkanols run above that of alkanes?
Is it simply because the only difference is the hydroxy group?
Is it simply because the only difference is the hydroxy group?
That you talk aggressively or are sad.
I already feel totally drunk
Hello, I wanted to ask what would happen if someone injected themselves with disinfectant? Would it be poisoning? Would it be fatal? (I just find it interesting; I often wonder about things like this.)
Why does the equation -Q=/\U hold? That doesn't make sense. The internal energy should also decrease whether heat is released or not? That would mean, for example, that it would be exothermic (U is negative) if heat was absorbed (Q is positive). Can someone explain this to me?
Hey I honestly don't understand how you can tell whether something is an acid or a base. How do I know, for example, that HPO4 2- is a base, but NH4+ isn't? I know that to be an acid, it has to have at least one hydrogen in it. And there's something about the polarity….
Let’s say it, there’s the homologous row of alkanes.
The alkanes form, so to speak, the word stem during the designation and also the backbone of the molecule.
The homologous series of alkanes should always be memorable, without which is nix. So methane, ethane, propane, butane, heptane, hexane etc.
For this, one can say that the same as in the case of the alcohols is of course also available with double/three bonds (alkenes/alkines) or other groups.
But we stay with alcohols:
If you have a simple alcohol now, you simply have a methanol, ethanol, propanol, butanol, etc. In the case of more than one hydroxyl group, there is of course also another designation, i.e. ethane-1,2-diol (known as ethylene glycol) or propane-1,2,3-triol (known as glycerol).
There are many different arrangements in general.
In addition, even with a single hydroxyl group, there is this effect from the third carbon atom that it can be arranged at different points. Therefore there is also a difference in the molecules propan-1-ol and propan-2-ol and in all others, of course.
Your expression is still developmental.
Probably you mean the boiling point curves.
Of course, this is due to the OH group, since it develops larger intermolecular forces which must be overcome by energy supply.
My teacher formulated the question.
Thank you.