Why do we use 2H20 instead of H20 when analyzing/synthesizing water?
In the formula
In the formula
Hi, in chemistry we're currently calculating mass using molar mass (M) and amount of substance (n). In the problem, aluminum and oxygen react to form aluminum oxide. The reaction equation is Al + O2 -> Al2O3, which I then balanced to 4Al + 3O2 -> 2Al2O3. I hope this is correct because I don't understand…
I'm currently looking at my first-semester schedule and I notice that some modules/lectures are held quite frequently in one week. For example, chemistry is listed in my curriculum as having a lecture period of 3 SWS. However, in reality, a full 6 SWS appear in one week. The internship is separate. Are these exercises/tutorials for…
My question is, what oxidation number does the positively charged nitrogen atom have? Normally I always look at the bonding partners and count the electrons depending on their electronegativity. In this case, three electrons with nitrogen, since both pull equally strongly, 3 each and another 2 electrons with from the single bond with the carbon,…
Because the gases hydrogen and oxygen normally form molecules of 2 atoms, namely H2 and O2. Thus, 2 H2 and an O2 to 2 water molecules burn 2 H2 O. Conversely, in the electrolysis, 2 H2 O are cleaved to 2 H2 and an O2.
In the equation, there must always be equal numbers of atoms on each side of each element, which is why the term “equality”. Atoms are neither lost nor are new ones (maintaining the mass).
I hope I could help you and a happy 2024!
In stoichiometric calculation, attempts are made with integer stoichiometric coefficients. Since oxygen appears as O2 you should write 1/2 O2. To avoid this, the equation is multiplied by 2 and then there is 2 H2O
Because oxygen in nature only appears as O2.
You can also write 1⁄2O2 but this is unnecessary.
The ozone layer tells you something?
Ozone is unstable and decomposes with time to O2.
Oxygen naturally occurs as both O2 and O3!
We say that any element under standard conditions is so and so of course (molecular) and exclude all unstable and metastable configurations. Sulfur naturally occurs, for example, as a S8 ring, so it is also taken over into the stoichiometric formulae and also in standartenthalpien…
To do this, it must first happen in nature and that denies your comment.