Why do the freezing points of alcohols rise?

For example, there are ethanol and hexanol. Ethanol freezes at -114°C, I believe, while hexanol freezes at -44°C. But why does less energy need to be extracted from hexanol to freeze, when hexanol is longer and thus forms stronger VdWK than ethanol? So, why hexanol needs more energy added than ethanol to become liquid is logical, but I don't understand the reverse.

LG

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willi55
1 year ago

In principle, you argue well, but you forgot that VdW forces do not play a role. Right is: Intermolecular forces are crucial.

Here are H-bridge bonds (strong force) and VdW forces (weak).

In hexanol, the chains are longer and thus the stronger H bridges between the OH groups can no longer interact so frequently. Therefore, the intermolecular forces are smaller. The VdW forces cannot replace the “loss” on the interaction of the OH groups.

JenerDerBleibt
1 year ago

You only confuse yourself with the mindset. Imagine a difference in height. When you start up at the top and run down, you will logically pass the mark (melting point) that is the highest.