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This is very, very much for today’s standards. You get several terabytes per server, usually in large server rooms (with several servers and a lot of storage), several pentabytes maybe.
Where’s Dad 2?
Two up. So 2^3 is 2*2*2. It is estimated that 2^10 is about 1000, so 2^60 is about 1000^6. Or 1000000^3.
You have an address of length 64. So 64 bits each with 2 possible states. Specifies a total of 2^64 possible states.
(This is the potency function.)
Okay, then it’s okay, I can explain. Later.
Yeah, those conversion roofs, etc. I never understood that. Gersde also because our teacher dss not explained hst. We started with CPU structures and how to convert anything into binary with IP dresses and so. And then, two hours later, we had NAND and NOR with logic.
To clarify the misunderstanding:
You wrote a comment, but you probably wanted to write an answer.
The message went to the wrong 🙂
Then why do you ask the question? Or do you not know that the number of values you can represent with N Bits is 2^N, always?
I know ^
I don’t know what you’re talking about, and what exactly it involves. Depending on the level at which you work, the address space can also be completely fired.
Ahh. I wanted to take a picture with IT communication. But after a year, I’ll ear out.
It’s hard to say, yes.
Exactly!
jup. In a CPU with an address space of 32bit, 4GB memory is connected.
What about electricity and electricity? So it would be with a 32bit CPU 2^32 bytes?
Because 16 exabyte RAM become quite expensive.
These are 16 million terabytes of RAM.
These are about 16 billion GB
A RAM bar almost currently around the 64 GB and the wariest for about 100€.
Let’s go. For 16 exabytes we need:
250mio RAM bar.
The time 100 is 25mrd Euro. Just for the RAM.
You also need boards that support this. Etc .
For comparison: the fastest supercomputer has in total just 2 PB on RAM. They’re still 8000 times less than the border. Say, you’d have to make 8000 of these supercomputers a club so that you can fully load the 64bit address space.
Because the amount of data of 2 high 64 data words is so large that the memory required for this is virtually unburdenable.
Think about how big the address room is…