Who can do that?
Can anyone help me with this task?
(1 votes)
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Yes. I would start with a drawing at your point: loading space 120 cm * 120 cm * 120 cm * 120 cm and you roughly indicate how many boxes fit in length, width and height. And from the drawing you make a formula. Then you can best imagine if you don’t have such a pale glow.
You could also share the total volume by volume per box. This works randomly because the numbers fit so well. Doesn’t always work.
Hello,
2, 4 side by side, 4 one above the other.
😎
Can you make an example?
You speak street German?
What an example you mean, I don’t understand. You just have to multiply.
However, weaker students can also have an Aha experience. Of course, it depends on how such tasks are incorporated into the teaching.
Precisely the double clarity tears the weak pupils even more into the abyss
I find such tasks good, as there is a simple solution and a complicated one.
In everyday life it becomes funny when it comes to wallpapering, the ceiling height is, for example, 2.60m at a roller length of 10.05m.
😁
Example = finished invoice
What you wrote, the FS probably didn’t pay attention
.
PS
I hate such tasks. In the case of crates of 50*50*20, the naïve should only be moved over the volume
Since the dimensions of the loading space are exactly integer multiples of the dimensions of the boxes, you can simply divide the volume of the loading space by the volume of a box and get the number of boxes that fit in.
Can you make an example?
🤨 You have the volume of the cargo hold (in litres. It is given in cm^3 with (120x120x120)cm^3). The volume of a box is (60x30x30)cm^3. Now divide the loading space volume through the box volume. Finished
is only by chance correct. Because the boxes fit so well to the dimensions of the transporter
Thank you very much