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Unterholz
1 year ago

Let’s take a normal cooker, which we fill, let’s say, up full of water (30cm) and measure in the middle of the height, i.e. at 15cm. Then the temperature of the wall is close to the water temperature.

more precisely: the wall is a resistance for heat transport. We have 20 degrees outside. In the pot 100 degrees. This temperature difference produces a heat flow which results in a certain temperature profile. Similar to when an electrical current flows through a resistor network. Therefore, the temperature on the outer wall is not equal to the water temperature…. And depends on the wall thickness and the wall material. But… first approximation, it’s close to the water temperature.

Tommentator
1 year ago
Reply to  Unterholz

Very nice explanation sketch(, we hope that the questioner also knows how power and resistance “works”🤔)

Unterholz
1 year ago
Reply to  Tommentator

Thank you… he/she can ask again….

Unterholz
1 year ago

So… Didn’t bother and make a measurement. Lack of aluminum pot I used a noble steel can. Floor diameter 15cm, height 15cm. Wall thickness 0.5mm, that is quite stable. The heating was carried out on an induction hob…. That is, the heat input from below is clearly different from a heating plate…. You can also see the temperatures below. The can was filled up to 7.5cm. It should also be borne in mind that the thermal conductivity of stainless steel is only 1/10 of that of aluminum. Water lightly simmering. The measured water temperature through the steam was 98GradC, ambient temperature 18GradC

Measured values

Floor, edge to induction hob, 73 degreesC

7.5 cm, filling height, 84GradC

10cm, 82GradC

15cm, near upper edge, 70 degreesC

I expected that the hot steam also heated the upper edge vigorously… but apparently the heat dissipation to the environment is quite violent and because of the poor thermal conductivity there is also not enough heat flow to build up a higher temperature. The problem is interesting – a reckoning under simplified assumptions would also be…

Picus48
1 year ago

The metal of the pot wall is in contact with the boiling water of etw 100° C. Outside it is in contact with the ambient temperature. A heat gradient forms within the wall. Therefore, the outside wall is slightly colder than 100°C. As cold, depends on the heat transport, i.e. also on the power of the heating plate.

Picus48
1 year ago
Reply to  WeiserSatz

If the lid is not placed, it remains somewhat cooler in the top of the pot. That’s right. But if it really sprinkles when the pot is closed and the equilibrium between the liquid phase and the steam phase has set, then it is also up and in the gas chamber 100° C. Theoretically. And if the lid is very heavy, then the temperature also rises above 100°C (thamping head;-)). In the autoclave where the lid is very tightly sealed, we had loose 121°C.

IZenMoenchI
1 year ago

Believe that’s the best thing to do.

By the way, head stab is pretty amusing.

LG

IZenMoenchI
1 year ago
Reply to  IZenMoenchI

but rather 90 degrees

IZenMoenchI
1 year ago
Reply to  WeiserSatz

It was a good laugh at the late hour! So a good question:D

hologence
1 year ago

that is not to say without details of the installation of pot and stove.

  • How is the pot warmed? Matching e-cardboard? Gas flame smaller than pot floor? Gas flame larger than pot floor? Induction heart?
  • how is the pot designed with regard to heat conduction from the bottom to the wall or from the water to the wall?
  • where is the wall temperature measured?

At the end, different temperatures will occur distributed over the pot.

Tormas
1 year ago

“Headed” 😎