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How best to get a grade of 4 in a math test?

ByCrischolab

Hello, I have a math test on Friday and I can't do anything. The following topics are covered: Intersection points of parabolas with coordinate axes position of parabolas and straight lines setting up parabola equations. drawing polynomial functions and sketches Symmetry and global progression. It would probably be best to focus on a few topics…

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gauss58
gauss58
4 months ago

P and Q must be exchanged according to the specified angle.

The intersection in the middle is S.

Since only one side (AB=1795 m) and the opposite angle γ=100.8° are known in the upper triangle ASB, a calculation over a plurality of equations to be set could be quite expensive.

I therefore proceed in reverse, set PQ = 1000 m, calculate AB and calculate the scale factor.

By means of sine and cosine set, AB can be calculated from below to above:

AB = 788,1211. From this follows the scale factor m = 1795 / 788,1211 = 2,277568

PQ = 1000 m * 2,277568 = 2277,568 m

Angle QAB = 60,86°; angle ABP = 18,34°

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soso0909
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soso0909
4 months ago
Reply to  gauss58

Thank you. How did you get to the 788,1211?

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gauss58
gauss58
4 months ago
Reply to  soso0909

All angles are known in the figure, in addition to the angles QAB and ABP.

Triangle PQS, with PQ = 1000 (sine set):

PS = sin(35,7°) * PQ / sin(100,8°) = 594,06371

SQ = sin(43,5°) * PQ / sin(100,8°) = 700,76709

Triangle SQB (sine set):

BQ = sin(79,2°) * SQ / sin(50,4°) = 893,37151

SB = sin(50,4°) * SQ / sin(50,4°) = 700,76709

Triangle PSA (sine set):

AS = sin(24,4°) * PS / sin(76,4°) = 252,48991

Triangle ASB (cosine set)

AB = √(AS2 + SB2 – 2 * AS * SB * cos(100,8°)) = 788,12112

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