What is the solution for gamma in this triangle?
I got 13.58 degrees for gamma.
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Can someone please explain number 5 to me? Thanks
5 / (2 * a_2) = tan(35°)
5 / (3 * a_2) = tan(x)
—————
x = 25,02°
γ =9.98°
from tan(35)=5/a1 a1 is obtained
.
now you can make
eta = 35+gam
tan(eta) = 5/(a1 + 0.5a1) …..(*****)
.
arctan(eta) brings eta
.
(*****)
who wants to replace a1 with 5/tan(35)
.
tan(eta) = 5 / (1.5 * 5/tan(35) )
5*tan(35)/7.5 = 2/3 * tan(35)