So I know how to multiply fractions, but I don't know where to write the x, since the x is in the denominator of the first fraction and the x is normal in the second fraction. Or is the x even squared?
LG
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Loading...For me the results are: x1= 2 x2= -1 However, the solution states x1= 1 x2= -3 Can someone help me because I don't understand what I did wrong (maybe it's a careless mistake but I make them very often and don't even recognize them)
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I'm not getting anywhere with this at all. It's about task 10, part B, subsections 1 and 2. Thank you very much
Hi, how can I solve this problem? My current approach looks like this, but I'm pretty sure it's not correct.
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This cuts out when x equals 0
This is not written clean: If the first x is to be under the broken line, it also has to extend significantly to this x.
The box division would help here, but is probably ignored?
x in the denominator.
1/(3x) and 1x/2 or 0.5x
Therefore,
(1*1x)/(3x*2) will be sure to
1/6
the x cuts away
But where do I write that x was my question?
it’s gone
yes, sure, safe, easy for the commander.
safe?