I just can't get the right answer (1 hour and 20 minutes). I wanted to apply the rule of three to a table with three columns. Anyone have any ideas? Thanks!
(1 votes)
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If you have a bit of time, I would really appreciate it if you could explain to me how to solve the tasks, as I don't know how to proceed.
A mechanic 4 cars per hour. (8 min + 7 min)
24 cars by 4 mechanics by 4 cars/h = duration1 in hours.
24 cars by 6 mechanics by 4 cars/h = duration2 in hours.
2 start one hour rather: 24 – (2 × 4) = 16
16 by 6 mechanics by 4 = duration3 in hours
Now you can calculate Duration1 minus Duration2 or 3 depending on which result you need.
even if he would need 4 times as long as each car has 4 wheels, you can count on this formula
My workshop is faster.
Step 1: Total time for a mechanic per car
Step 2: Total time for 24 cars with 4 mechanics
Step 3: Total time for 24 cars with 6 mechanics
Step 4: Additional working time of the two mechanics
Step 5: Time saving
Answer:1 hour 40 minutes (response a)
I hope that will help you
Thank you for the detailed bill, but there is a mistake of thinking, which is 15 minutes per maturity. This means you have to count 15 times 4 for the four tires. So a car= 60 minutes
probably chatgpt without own idea :(((
No! It is not specified with 15 minutes!!
Sorry didn’t recognize it, right?
How long does 1 mechanic need for a car?
Then you share the number of cars by the number of mechanics to find out how many cars a mechanic does a day.
Then you reckon the first time the second number and have the first working time. You do this again with 6 mechanics and just have to make them difference.
2 hours are right
Unfortunately, the right solution is 1 hour and 20 minutes.
otherwise there is a way of travel
Oh, but then you’re wrong with your solution, it can’t be that you don’t know how you get on it, because it’s wrong…
because I don’t know how to get the result :/
Why do you ask if you know her?