What is the output voltage of Ua?
Hello dear Gutefragen Community,
Unfortunately I can't get the result, can someone help me?
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The resistance of the NTC at 60° is read from the diagram (on the line for the 10 kΩ NTC): approx. 2240 Ω
(Note: previous incorrectly read value has been corrected).
Then you replace the parallel connection of R2 and NTC with a resistor.
The rest is pellet.
—–
Supplement for @ (how to read the chart)
“For the resistance of the NTC at 60° you read from the diagram (on the line for the 10 kΩ NTC): approx. 1150 Ω” – I don’t understand :-(. I read minimum 2.5 kOhm. Greetings e1
The diagram shows several characteristics for different NTCs. The slanted kΩ data refer to the R20 of the NTC used (R20 =resistance at 20°C). The line labeled with 10 kΩ is relevant for the task. On the line, the point of intersection with the vertical 60° C. line is sought and, starting from this point of intersection, the resistance of the NTC at 60° C. is read off on the logarithmic y axis.
That’s true. With sharp eye you can see the intersection at 2240 Ω;-)
I’ll fix it.
I’d read it like that.
I absolutely agree. But I read at least > 2000 ohms. Maybe I have a kink in my look. LG e1
Correction: Ua = 1.4 V (rule in denominator)
LG H.
There was a mistake. The total resistance of the voltage divider (in the counter) is not 15k+18k, but 15k+parallel circuit.
I also come to the conclusion that there is a mistake here. I once again looked at the formula for the loaded spg divider and my solution is not correct. I’m not sure yet. Greetings
That’s right. I blew a fatal mistake. Thanks for the tip.
LG H.
I am
The parallel circuit 18k and 2.2k for the NTC
1/ (1/18k + 1/2,2k) = 1960 Ω
The voltage divider thus yields
12V/(15k+1960) * 1960 = 1.39V
Also fits well to the offered 1.4 V
Determine resistance from diagram.
Calculate total resistance of the two parallel resistors.
Calculate voltage drop.
This is exactly what I’ve done six times. Unfortunately, my results do not match any of the possibilities. I always lie between 1.3V and 1.5V. The value for 1.4V reckoned does not match the characteristic curve. What am I doing wrong?
1.4V fits well if you read anything about the 2230…2240 Ω…
The 1.4 Vs seem plausible to me.
Ra should be around the 2000 ohm. Then it should be about that 10,6V drop off at R1.