What is the current at point A in the circuit shown?
The correct answer is: 200 µA
How is the calculation done?
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Hello
It must be seen that the current at A flows through the resistor 0.12 MOhm and that the widths 120 kOhm and 0.12 MOhm are connected in parallel.
In the case of resistors 1/Rges = 1/R1 + 1/R2 applies.
This leads to the formula Rges=R1 *R2/(R1+R2).
For R1 = R2 (then mikedresden!!!) follows: Rges = R12/(2R1) = R1/2 = 60 kOhm.
For this purpose, the resistor 100 kOhm is in series, so the total resistance is 160 kOhm. Because of the ohmic law R=U/I, it follows for the total current
Iges = U/Rges = 64 V/160 kOhm = 0,0004 A.
The voltage U3 =100 kOhm * 0.0004 A=40 V thus drops at the 100 kOhm resistance.
The voltage U1 =U2=64 V −40 V=24 V then remains for the parallel circuit.
The current duch the resistor is 0.12 MOhm
I2 = 24 V/120 kOhm = 0,0002 A = 0,2 mA
(With Ohm = V/A)
You can also make the bill with Ohmschem law, knot rule and mesh rule:
R1: Resistance 120 kOhm
R2: Resistance 0.12 MOhm
R3: 100 kOhm
U1 =U2 (parallel circuit)
U = U1 + U3 (mass rule)
Iges = I1 + I2
I1 = U1/R1
I2 = U1/R2
Iges = U1/R1 + U1/R2
U3 = R3 * Iges
U3 = R3 (U1/R1 + U1/R2) = U1 (R3/R1 + R3/R2)
U = U1 + U3 = U1 + U1 + R3/R1 + R3/R2) = U1 (1 + R3/R1 + R3/R2)
U1 = U/(1 + R3/R1 + R3/R2) = 24 V
u.s.w.
Un: Voltage on resistor Rn
Hello!
Way of Solution:
Greetings
I have calculated 0.0004 A
then write 0.4mA or 400μA that you can read at least
False
For what? That would be wrong.
already clear that it is the total current (not what was asked) but I would still not write it with four decommissioners, but simply go one or two units smaller ^^^