Bytobi2247
Hello,
I have one even and one odd symmetry line, and I wanted to ask if my approach is correct, since a friend suggested that with the even symmetry line, the resistance also falls out in the second fall and doesn't split. Which approach is correct?
My approach:
straight symmetry:
odd like this:
(1 votes)
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You should be able to use it for something. It could have something to do with magnets, or maybe with eddy currents or something?
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I would say it depends on the context of the circuit. In principle, the equivalent (right side of the representations) should be such that the resistance value in total behaves as at the original terminals. This is the case in the upper examples. The resistance between the terminals continues to be R after division.
In the lower example, this would depend on which part the equivalent of the division belongs. If one has a circuit in which there is a certain symmetry, I divide the circuit along the line of symmetry and the line then runs on a component as shown below, then one half of the circuit subsequently formed applies that the component drops. This, however, must again appear at the other half, because otherwise it would change the entire circuit.
You can now use the same principle in case 2 in the lower picture. If the line of symmetry is straight, it would be R/2 in row to R/2. If it is uneven and you do not know the measure, you would have to pack R either to one or the other half of the circuit. It is not possible to delete it completely, otherwise it would not be there from the outset.
I have no idea.
At my time there was 1 parallel connection and 2 series connection.
Then you can calculate everything and finish it without blue strokes.