Can someone simply explain what the f-number means on camera lenses? And what are the most popular f-numbers? I've already googled it, but I'm always getting technical terms thrown around. And I've also seen that some lenses, for example from Fujifilm, only have f4, while others have f1.4-4.5. Why is that?
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There are not really “popular f numbers”. That would be just like the most popular trains in the car. You drive in the gear you need.
F stands for Focal Ratio (opening ratio) and indicates the light intensity. The lower the f-value, the more light intensity has an objective. That was already explained.
With almost any lens, you can also set the f value higher than the lowest value. To achieve a larger sharpening range and also edge sharpness improves, but the image becomes darker. On the other hand, you have less sharpness at a low value, the edge sharpness decreases and the lance strength increases.
In portrait photographers, lower f-values are more popular because one often prefers an unsharp background. For landscape photographers, higher f-values such as f/8 or f/11 are more popular because everything is to be crisp.
F4 usually means a fixed focal length or even lenses with different focal length ranges, but continuous diaphragm. F1.4 – 4.5 is a lens with different focal length range. The f 1.4 stands for the maximum open aperture at the lower focal length and the 4.5 for the final focal length.
Specifically, the designation from the lens above…XF( higher-quality lens series) means 16-80mm (minimum and maximum focal length) f4 (continuous aperture of 4) OIS (stabilized) WR (dust – splash-proof)
There are not necessarily the most popular “F numbers”. A lot of light intensity brings you in theory a low ISO, shorter closing time, a lot of release. However, this is also the great disadvantage, because a lot of light intensity / wide open aperture (low f – number) can also mean that you don’t get your motif in a reasonable way and thus ruin your image. Then you have a small ISO and a little picture noise (which can now be removed by programs and is far from as relevant as before), but also a bird (or whatever) that lies only half in the sharpness (not rectible). Otherwise, there are aids in addition to detangling, which makes a partially negative high light intensity superfluous (unseen if a great deal of release is desired or some extreme situations like at night, if you cannot be exposed for a long time, because you can e.g. clear polar light rays or round stars etc) such as tripod, picture bar in objective and/or camera. Many Stabis are theoretically so good that even with longer focal lengths you can be exposed quite long. With my 300 (450KB), for example, 1/60 only with Stabi from the lens (and other lenses can be longer) and these are already times that are completely practical when you photograph animals or other moving things.
A high intensity of light only brings you something if it is tolerable to the motive or it is absolutely impossible to do otherwise. Otherwise, you can also easily use light-smooth lenses if you have the choice. Don’t let lights dazzle you if you can’t use it wisely.
f represents the focal length.
And the “f-number” as you call it so beautiful is the aperture, which is always given as a relation to the focal length. Thus, f/4 ( focal length ÷ 4) means that the aperture is a quarter of the focal length. At 80mm focal length, 20mm aperture.
The smaller the number of apertures, the larger the aperture and a large aperture is basically a good one.
It is relatively complicated to build zoom objective that have a constant aperture through the entire zoom range.
Since the aperture is given as a ratio to the focal length, the aperture number naturally changes as a function of how far you zoom in.
It makes the lenses big and harder… since I myself have a 70-200 F 2/8 I understand even less why everyone wanted to turn that on me 1.3 kilos this Oschi weighs….
f generally means the focal length.
The larger the f (the longer the focal length), the stronger the target object is raised in the image.
But what you mean is the number of apertures, or f-number = f#.
The smaller this number is the larger the aperture and thus more light comes to the sensor.
The f stands for the diaphragm. Just explained.. So if you have a low number, for example 1.4 then the lens is super suitable for night photography as more light comes into the camera. So the aperture is very wide open, with a higher number. for example 4.1, the objective requires more light.
Simply explaining it is really hard, doesn’t know how to rewrite all the things 😂 Where I personally prefer strong objective. So a small aperture, in most cases you can adjust the aperture so that less light can fall and you can also photograph well on the day. And if the lens is strong, you don’t have to adjust the ISO to such an extent, and then you’ll get less picture noise (i.e. granular image)
Wrong.
Quote: “That f stands for the diaphragm.” The f stands not for the aperture, but always (in physics and optics) for the focal length.
The abbreviation for the aperture (corresponds to the aperture/width ratio) is the f-number = f#.
This is defined as the focal length of the objective divided by the free diameter of the aperture. So f# = f / D
The questioner just wanted to get it explained. No one understands
Supplement:
I explained in my own answer to this question (relatively simple) what is the focal length f and the focal length/opening ratio f#.
That is the questioner, if he does not understand, then he should ask.
A physically and technically wrong answer can definitely not help him (no matter how intelligent he is and what pre-knowledge he has).
It’s about the open panel of an objective. Depending on the focal length, the possible naximal open diaphragm usually varies. However, there are also (very expensive) lenses that allow this open panel to pass through. The smaller the number, the larger the aperture. That’s good, because that means more light on the camera sensor. And more light means that you can afford shorter closure times and thus less blurring. Also the ISO value does not have to be screwed up and this means cleaner, less rough images.
Dear FatherAlfonso,
I appreciate you as a real answerer.
This time you’re wrong.
The focal length has absolutely nothing to do with the diaphragm.
Maximum indirect – because “f” indicates the greatest possible aperture.
Although I have a 55mm lens of Canon (1:1,2), I have never had to photograph with the greatest possible aperture. With such a light-strong objective, exposure times of 250-1000 thousand tumblers are sufficient.
Hello
f or more precisely the 𝆑 forte character (U+1D191) is the maximum aperture value of the entrance pupil. Because f is actually the Focal Value (Fight)
In principle, the value focal length : entry lens diameter is the “aperture” value.
In the case of aperture f1, the diameter of the entrance pupil corresponds to the focal length.
f is less than 1 and the lens diameter is greater than the focal length or the rear lens is greater than the front lens.
f values above 1 mean the lens diameter is smaller than the focal length.
A f value is always a reciprocal/break value. f2 is a half, f4 is a quarter, f8 is an eighth.
With the value, one can “estimate” the maximum “lightness” of an optics, but the actual transmitted amount of light is the transmission value (T). The f value is a simple Pi x thumb calculation based on the basic geometry of an optics, which can be measured with a slider and projector or collimator. Light is reduced by medium passage and extraction/air passage, which means that each lens in the optics “freezes” light in the 1 digit percentage range. A focal length with 3 lenses has a higher transmission than a zoom with 12 lenses with the same aperture. If one builds transmission values on a uniform standard, one has to increase the aperture of the front lens in the optical system. There are tiny 50/1.4 small image optics with 43mm filter thread (Leica Summilux) and zb the Sigma Art 50/1.4. One reason is the Leica has only 7 lenses the Sigma has 13 lenses. Sigma had to compensate for light loss of the many lenses with a larger front lens, the optics is less “effective”.
The number of apertures or the pupil ratio and thus the field depths are linked to the f value in relation to a defined resolution (admissible scattering circle). There is depth sharpness and depth of field depending on which end of the optics. On the projection plane (film or sensor) one has depth of field. The real depth of field is not identical for all lens designs of the same focal length.
http://www.pekt.de/lexikon/physik/f-zahl/5440
http://www.elmar-baumann.de/fotografie/frage.technik.blende-und-schaerfentief.html
These f numbers are the light intensity. The more light a lens passes, the smaller this number.
The number is the result of a ratio ( focal length in mm / diameter of the entrance pupil in mm) Example: focal length 50 mm, entrance pupil 35.7 mm, f:1.4
“f” is the focal length, and not the aperture size.
It has a lot to do with the light intensity of an objective.
1:1.2 is almost the light intensity of a human eye.
Nee the focal length is the MM indication of the lens, F is the aperture or light intensity
Nene, that’s right.
f = the space holder for the focal length.
f/1.4 is only the aperture number, this is a ratio to the focal length.
Right.
The focal length of each lens is denoted in the optics (physics) by the letter f and is indicated in the unit of mm.
The aperture, more precisely the focal length/opening ratio, indicates the light intensity of the objective. This ratio is called f-number and is abbreviated to f#.
The calculation is: f# = f /D
Since both the focal length and the opening diameter are measured in millimeters, the value of the f# is dimensionless.