ByXXXXXX77
Hello,
I have some problems from the book here and would like to know what I have to do. It would be great if I had an example solution for each problem.
(1 votes)
Loading...In a company, all employees report the length of their commute and the type of Means of transport were recorded. In March, this resulted in: a) What percentage of employees have a commute of 10 km to less than 25 km? ………………………………………………………………………………….. ………………………………………………………………………………….. During the summer months, 10% of employees who used public transport or…
Hey, The task is: Prove geometrically that there are infinitely many orthogonal vectors for a given vector. Distinguish between vectors in space and vectors in the plane. So I would say that there are infinitely many multiples of a vector that is orthogonal to a given vector, so that this orthogonal vector can be infinitely…
Heyy, What is the average score for the Kangaroo Test in 9th grade? Thank you for your answers
(2^x-3)!=x
When analyzing the curve of a rational function, does one also need to consider the behavior at +/- infinity? I have several solutions where the behavior at infinity was not considered. And what is the difference between behavior at +- infinity and behavior at the poles? Do you use L'Hospital for both?
For task 7), you need to consider which factor you need to multiply the individual coordinates so that complete numbers are obtained. Either you make it easy and multiply with 10’s (i.e. you’re just leaving the comma) or you choose the smallest possible factor. If you have found a suitable factor, you must multiply the vector with the reciprocal value of this vector so that the values in the form r* Vector a are the same.
Example 7a): Here, you could either simply multiply with 10, i.e. move the comma of the coordinates by one point to the right, and would have as vector a: (515 -15) and would then have to multiply it with the reciprocal of 10, i.e. 1/10. Or you multiply in this case with 2 (because ,5 means “half”) and come to 1/2* (1 3 -3)
Task 9): Here you can summarize the vectors as well as variables (x, y, z) – just think away the arrows…
Task 11): here I would first write down the corresponding coordinators of the vectors and then “calculate them as indicated.
Example 11a): a=(2 2); b=(1 1), thus results for the left side a+2b: (2 2) + 2 * (1 1) = (2 2) + (2 2) = (44). If the right gets out with d-2c, the equation fits.
7) You are looking for a common factor of the three components of the vector
Example a)
9) This is the same as with real numbers and variables
Example a)
11) You write all vectors first:
and then you calculate the vector sums component-wise to the left and to the right and compare whether the same sum vector comes out.
The equation a) is therefore correct
Would 7 b) vector 3.5 1 2.5 then be multiplied by 2?
Or otherwise: If you multiply the components individually with 2 to obtain integers, then you need to multiply the entire vector with r=1/2 (the reciprocal of 2) so that it remains the same vector.
No! If you multiply in b) with 2 then you will create one new, other Vector as you double its “length” (mathematic: amount). You have to a common factor 3 components which is again 1/2 = 0.5, because:
At 7., you need to multiply the vectors with any factor so that only integers are present in the vector. Thus, at a), for example with 2, so that it is in the vector (1,3,-3). The value of the factor is then your r. So 1/2 * (1,3,-3) is the same as the vector from the task.
Task 8 is actually quite simple. You just have to compile the same variables. (a) (3+5-7+2-1)*a = 2a)
Task 9 can be solved with a drawing. If you draw the left side of the equation from the same starting point, you must arrive at the same point as when you draw the right side. Thus, with a) vector a + 2 times vector b must lead to the same point as 3 times vector d and 2 times vector c back.