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Halbrecht
10 months ago

1/5×5 – 1/2×4

f”'(x) = 5*4 * 1/5 * x3 – 4*3 * 1/2 * x2

= 4×3 – 2/3×2

4×2 * (x – 2/12 ) = 0

xwp1 = 0, wp2 = + 2/12

MichaelH77
10 months ago

twice derive

set the second derivative zero, after x
the associated y-value you calculate with f(x)