Weight of bird cage with flying birds?
Suppose you have a large bird cage on a scale and it weighs 20kg.
Now you put five birds in, each weighing 1 kg. Then the whole thing weighs 25 kg.
Now all the birds start flying simultaneously while standing in the air. Does anything change in their weight?
I heard somewhere that the weight doesn't change when the wings are exposed to air. So the scale stays the same?
If so… suppose the cage had open sides and the birds were simply flying through. Should the weight also fluctuate at that moment?
PS: The weight information is of course only symbolic and is not intended to correspond to reality.
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In a cage closed (airtight) nothing.
In the case of a wire/glitter cage, the display on the scale would be less because the air pressure by the wing impact only presses to the bottom of the scale to a limited extent.
Everything without the important studies with Newton or Max Planck, as from Iks72 presented here.
Contrary to this, the display weight on the scale is reduced by the falling bird in the cage, but not canceled except at the starting point of the case. When impacting the soil, of course, a greater weight will be displayed than the bird would rest on the ground.
Well, you don't explain anything, you don't need to be an important student.
but important studies with false statements – this is the hammer.
And that with the impulse currents is caps here.
First of all Newton: If the birds are in the air, then the resulting force on them is 0, that is to say to the weight force FVogel, NOCH acts on the bird, namely from the cage (or directly from the air in the cage) with the size FKäfig = – FVogel. According to Newton's Actio Reactio, a force of the bird acts on the cage of – FKäfig = – FVogel = FVogel. In addition to its own weight, the weight of the bird FVogel continues to act on the cage.
Since Max Planck 1908, this has been easier to explain with impulse currents: The bird gets a pulse current from the gravity field. If he wants to stand, he has to get rid of it directly, so he flows through the air through the cage into the ground. Here too it is clear that bird standing in the air has the same effect as the sitting one.
And something else. If the bird doesn't fly, just fall down, the cage is really lighter. Why?
Again, Newton: Because here the balance of power is not 0, but is only FVogel, FKäfig falls away, so Actio and Reactio also falls away and thus the additional force on the cage.
And again Max Planck and the pulse currents are simpler: if the bird falls down, the bird gets a pulse current from the gravitational field, but he keeps this pulse (then he moves down) and thus does not release the pulse current to the cage, so the cage "nears" from the bird.
Very technical 😀 But understand. And how does it work with a bird flying through the cage?
He's gonna get out of the bar on the other side.
Scissors