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Routing task impossible/conditions not possible?

ByKGamer676

Hey I have a task to solve How does task c) work? Two railway lines represented by the functions 𝑔 and β„Ž must be connected be connected. a) Determine the equations of the functions 𝑔 and β„Ž. 𝐴(βˆ’2|4), 𝐡(2| βˆ’ 2) and 𝐢(6| βˆ’ 4) g(-2)=4 h(x)=-0.5x-1 b) Explain which conditions the connecting piece should…

Math homework?

ByMyNa12

Hi guys I have a question about my homework. We went through the material last year and now we've received a kind of assessment.πŸ₯² Can someone maybe help me out again to make this work? So I need help with all the tasks and I have to do my homework again tomorrow and have to…

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Rhenane
Rhenane
11 months ago

This is because f”(800)=0 is not true!

The point (2000|50), i.e. f'(2000)=50 as you have already noted correctly, is clearly visible here. And with this equation you can determine the b already!

b=92/4000=-23/1000=-0,023

With the equation f”'(800)=0, you come to b=-117/5000=0,0234, so not -0,023, so when solving the equation system, the empty amount comes out.

The low point of f’ (i.e. f”'(x)=0) is calculated at x=786,32 and not at x=800.

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GurkenCombo
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GurkenCombo
11 months ago
Reply to  Rhenane

Thank you so much so if only one variable is missing you just need one more info. Have helped me very much and give you the star

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Rhenane
Rhenane
11 months ago
Reply to  GurkenCombo

Right, 4000b+142=50 you can change directly, so you don’t need any further equations.

You need just as many features/equalities as you have unknowns to determine a unique solution. If you have more “safe” information (not as here, where it can be quite inaccurate, as you see), then you only take as much of it as you need.

And using values that make the unknown(s) disappear completely, don’t help anymore, as with you at f'(0)=25! With the result 25=25 you only show that the statement f'(0)=25 is correct. :

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