Why in structural formula 4h but in the normal formula C4h6O6?
Hello, I'm taking my chemistry exam next week and have to prepare for a few problems. I have to write protolysis equations for tartaric acid. The structural formula shows that there are 4 C, 4 H, and 6 O, but Google gives me the formula C4H6O6. Now I'm wondering how to get from 4 H to 6 H 😬
At the Cs on which the OH groups hang, a H is also present. This is only not shown so that the structural formula is clearer. Otherwise you would have three-bind Cs in the molecule.
The formula is a skeleton formula. In this, the carbon atoms are simply represented as corners or bar ends and all H atoms bound to carbon atoms are omitted. The number of H atoms results from the four-binding capacity of carbon. Ethan has the skeleton formula — so just one line.
And please write the element symbols big, small really hurts.