ByMassa393
Can someone please help me? I've been trying to solve or understand this for an hour, but I still don't understand anything. How should I do this? Can someone please explain it to me? I need help.
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Loading...Good morning, I discovered a beautiful coin in my wallet today. Is it worth more than 2 euros? If it's worth anything, do you think anyone would buy it?
Task 3 Quadratic equations Bridge construction: A bridge arch can be described by the equation y = -0.008x² + 80, with the vertex directly above the origin. Calculate the span of the arch.
Can anyone solve the following problem? It involves trigonometry and body calculation. Thanks
How do you divide sums? Is there a recipe you can always use, or do you always have to approach the problem differently? I am currently having problems with the following tasks:
I need a solution and explanation for the following tasks! / = fraction bar ^ = power a) 4/2-3x + x/x-4 b) 4x/4x – 4x/4x c) 1/2+x + 2/x-2 d) 1/x^2-1 – 1/x^2 e) 3x/x^2-4x – 2 f) 5/x-5 + 5 g) 8/9x – 6-x/3x^2 + 2-x^2/x^3 h) 5x/2x^2 – 2/1-x + 2-x/xx^2
(a)
There are only 16 possibilities for four litters, so my simulation plan looks like this:
(b)
At least three coats of arms appear in the list of possibilities 5 times. Exactly twice coats of arms and twice the number is found in the list of possibilities 6 times.
(c)
If a 1,2,3 is thrown, the event is instead taken on coats of arms.
If a 4,5,6 is cubed, the event number is instead assumed.
I am irritating :
perform a simulation and the Ps
First you throw the coin, then you got 50/50. Left: head, right: number. After the 2nd litter, both chances are again divided into 2 branches: 50/50 whether head or number and so on: Now you’re looking for how many ways you get at least three times coats of arms out, count them and then how many ways you get 2 coats of arms and 2 numbers out. That’s the most likely.
2) you must try yourself, I don’t know what’s meant by “estimate”.
3) … Stop instead of 2 options per point, now 6.