unloaded voltage divider: effective voltage?
Can someone please help me with the task and the calculation method.
A sinusoidal input voltage of 163 mV (peak to peak) is attenuated by 38.5 dB by a linear filter. What is the effective voltage in microvolts at the output of the same filter?
You have to recruit yourself.
Find the formula for damping on the net. Note: These are tensions and not performances.
Convert the formula to u2.
Rechne u2.
Convert to the effective value.
That’s all I want to do, because we’re not your homeworkers.
I just want to find out how to use or convert the formulas.
I have the result myself.
Thank you for your answer
Write your way of calculation here and the result. Then I’ll check it.
It’s wrong!
Take a closer look at how you deal with log.
And why do you suddenly have any resistance in the bill? You don’t need them, and you don’t know anyone.
Geg:
Top tip = 163 mV
attenuation = 38.5 dB
Ges:
U2
lace tips = tip x 2
lace = lace lace / 2
Peak = 163 mV/2
= 81.5 mV
U Peak = U Effective * 2
U Effective=U tip / 2
U Effective = 81.5 / 2
= 40.75 mV
attenuation = 20 log (U1 / U2)
38,5 dB = 20 log (U1 / U2)
38,5 dB / 20 = Log (U1 / U2)
1,925 = Log (U1 / U2)
10^1,925 = (U1 / U2)
(U1 / U2) = 84,139mV
U1/U2 =R1 + R2 / R2
Unfortunately, I don’t get any further.
Since I don’t know how to keep going.