Tree diagram incomprehensible?

Hi, we're currently studying tree diagrams, and I'm pretty good at the topic itself, but I find the written exercises completely incomprehensible. I don't understand them and I never know what to do; it just doesn't make any sense to me. Am I stupid or something? No joke? For example: "Four queens, three kings, and a jack are taken from a deck of cards. Nina draws two cards one after the other. What is the probability that Nina draws a queen and a jack when she puts the first card back down?" So, what should I do? Where do I start? 😭😭

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Rammstein53
11 months ago

I would only create a tree chart if it is explicitly requested. In this task, I do not see any need to make the solution superfluously long and complicated.

Suppose it is a card game with four 4 colors of each type. Unfortunately, no statement is made. There are card games of different composition.

Among other things, four ladies are taken before the trains.

Probability, then a lady and pulling a boy is zero.

Halbrecht
11 months ago
Reply to  Rammstein53

I see it differently than you (my answer )

Your interpretation :Mindfuck

my : strange approach

but with the P tasks there are also so many variants

Halbrecht
11 months ago

in the urn are

4 D, 3 K and 1 B

.

You start with three branches

D K B

Because the first card is returned, everyone is back and coming to each branch again D K B

.

so there are 9 paths

.

What paths are interesting?

D B and

B D

D B is 4/8 * 1/8

B D is 1/8 * 4/8

together

8/64 = 1/8

.

But I do not exclude Rammstein’s interpretation of the question.

thetruedon
11 months ago

So you know by the task that the tree has two branches (2 cards to pull one by one)

And you know that the probabilities are identical at both levels (refer)

And you know the probabilities for the 3 branches (bube, dame, king)

So:

A tree of three branches has and each branch has three branches again. 8 cards of which 3 kings so P(roy)=3/8, 4 ladies P(dame)=4/8 and 1 bube P(bube)=1/8

You ever write that to the branches.

And at the second branching plane again because of it.

Now you can easily calculate the probabilities by multiplying the Bube along the paths and dame contain the probabilities and then, if there were several possible paths, add the expected probabilities