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gauss58
2 months ago

I call the base from D to AB F and the base from C to AB I call G.

DF = CG , due to the parallelity of AB and CD

cos(60°) = AF / 6

AF = 3 cm

GB = 12 cm – 6 cm – 3 cm

GB = 3 cm

Consequently, β=60°.

peer80
2 months ago
Reply to  Sinawunderli

Nix Lotus. Lot foot point. From D at right angles to AB and thus 90 degrees.

DerKorus
2 months ago

Since the lines AB and CD have to be parallel, you can find the angle at D.

This angle minus 90° gives you an angle in a right angle triangle with point A. Point D and a point on line AB so that it becomes perpendicular.

Then you get the length from point A to this new point via trigonometry.

In turn, you can calculate the length of the same triangle on the other side (B/C/new point right angle to C on line AB).

Then again trigonometry to determine the angle.

DerKorus
2 months ago
Reply to  Sinawunderli

I won’t do that.

I’ll give you the approach, that’ll help a whole piece, but you can calculate everything yourself. It’s your homework and not mine.

notting
2 months ago

https://www.youtube.com/results?search_query=lehrerschmidt+trapez+winkel on the channel there is much more to the topic.

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