Hello,
cannot fully understand the step from the first to the second derivative, and even less so from the second to the third.
It would be cool if someone could show me how to calculate it.
Merce
(1 votes)
Loading...Hello, I need help with tasks a and d. I've already done tasks B and C. We're supposed to use the sine and cosine theorems. I don't understand tasks A and D. Can someone please explain them to me?
and I can't figure out b) it would be great if someone could write down the calculation method for me because I can't figure out the solution: ZSB is in the range 19.991mm to 20.009mm cylindrical grinding: 19.9955mm to 20.0045mm
How would you calculate the intersection point of the following line? Please provide the calculation step.
Hi everyone, I'm taking a math exam today and used this problem for practice. However, I don't quite understand problem b). The operator is "Determine," so I don't have to calculate anything. However, I'm not entirely sure about the approach: For the height of the dike: f'(x)=0 (?) For the land side, I need to…
First, re-form the fracture:
And then apply the product rule. Do not forget the internal derivation of the clamp.
But thanks the part was not so heavy, it’s more about the other derivatives.
If you understand, you can also do the other derivation. Just the same principle. Forming and product rule, otherwise you should not need anything. Just become very long and annoying terms.
Hm, okay tried with the quotient rule and it became very confusing. Try the product rule.
Partial breaking down:
Forming:
Now the discharges can be easily determined with the potency rule:
Even if you do not recognize it right away, this solution is identical to the solution in your question.
Oh, man, I just think I’m still forming and using the potency function is the easiest.
f(x) = x / (x2 – 4)
f'(x) = (1 * (x2 – 4) – 2 * x * x) / (x2 – 4)2
f'(x) = (1 * (x2 – 4) / (x2 – 4)2) – 2 * x2 / (x2 – 4)2
f'(x) = (1 / (x2 – 4)) – 2 * x2 / (x2 – 4)2
f”'(x) = (- 2 * x * 1) / (x2 – 4)2 – ((4 * x * (x2 – 4)2 – 2 * (x2 – 4) * 2 * x * 2 * x2) / (x2 – 4)4)
f”'(x) = (-2 * x / (x2 – 4)2) – (4 * x * (x2 – 4)2 – 8 * x3 * (x2 – 4)) / (x2 – 4)4)
f”'(x) = (-2 * x / (x2 – 4)2) – ((4 * x / (x2 – 4)2) – 8 * x3) / (x2 – 4)3)
f”'(x) = (8 * x3 / (x2 – 4)3) – 6 * x / (x2 – 4)2
f””(x) = ((24 * x2 * (x2 – 4)3 – 3 * (x2 – 4)2 * 2 * x * 8 * x3) / (x2 – 4)6) –
(6 * (x2 – 4)2 – 2 * (x2 – 4) * 2 * x * 6 * x) / (x2 – 4)4
f””(x) = (24 * x2 / (x2 – 4)3) – (48 * x4 / (x2 – 4)4) – ((6 / (x2 – 4)2) – 24 * x2 / (x2 – 4)3)
f””(x) = (-6 / (x2 – 4)2) + (24 * x2 / (x2 – 4)3) + (24 * x2 / (x2 – 4)3) – 48 * x4 / (x2 – 4)4)
f””(x) = (-6 / (x2 – 4)2) + (48 * x2 / (x2 – 4)3) – (48 * x4 / (x2 – 4)4)4)
Thank you for your effort!