Task: On the trail of alcohol adulteration: Determine the names and structural formulas of the four substances and justify your classification, taking into account the investigation?
On the trail of alcohol adulterators. During a raid in the basement of an illegal distillery, the criminal investigation department found four unlabeled canisters of colorless liquids. Samples were taken from these and examined in a chemical laboratory. The yield tested the following results:
a) All four liquids are pure substances consisting of hydrogen, oxygen, and carbon. Oxygen is bonded to the C atom in each case.
b) All four substances are flammable.
c) The substances do not exhibit uniform solubility behavior. Substances 1 and 2 are soluble in both water and heptane. Another substance is highly soluble in heptane but sparingly soluble in water. The last substance exhibits the opposite solubility behavior.
d) Substance 4 is technically produced from 1 mol of carbon monoxide and 2 mol of hydrogen
e) Substance 2 can be produced industrially from 1 mol of ethylene and 1 mol of water vapor.
f) All substances have the same number of oxygen atoms.
R) Substance 3 contains two more carbon atoms and four more hydrogen atoms than substance 2.
h) 0.2 mol of substance 1 weighs 12 g.
Determine the names and structural formulas of the four substances and justify your assignments, taking into account the results of your investigation. Write down reaction equations for reactions d) and e).
In the text of the linked question: "oxygen is in each case C 1 -Atom bound."
I'm still enjoying chemistry right now!? 😂😥