What's up guys, I have an IT teacher who's gotten fed up with me, so this is one of my last resorts. We did an assignment where we had to find the 199th subnet: IP: 192.170.0.0 Subnet: 255.255.128.0 My calculation method: 2 to the power of x = 200 x = 8 (the teacher calculated…
Hello everyone, following question on the topic of subnetting: How do you calculate problem 4? I understand everything else before that. I just don't know why, in problem 4, the subnets in the third octet always increase by 8. Or why the top subnet starts at 172.30.224.1 . That's the answer I learned at school,…
We're starting to learn Java in a few weeks, and I'd like to get started now. I've already watched a few videos by Junus Ergin. Now our instructor told us that if we wanted to get into it now, we shouldn't just type out code from books or videos, but rather come up with a…
Hello everyone, I am currently working on subnetting and have the following task for which I need an explanation, as I am not 100% sure about my result: "You are required to set up six subnets for a customer. However, only one class—a Class C network—is available. You have been given the system address 192.168.5.10."…
Let's say I have the IP address 192.168.10.0/28 and want to create 20 subnets. To do this, I calculate 2^5 = 32, so I can create a total of 32 subnets if I steal 5 bits from the host portion. The problem is, the host portion only has 4 bits, with a prefix of 28….
Hello, We all know the 3 private address ranges: 10.0.0.0/8 172.16.0.0/12 192.168.0.0/16 I would like to set up a /12 network, but not in the 172.16-172.31 network but in the 10.0.Host.Host – Area it and have additional networks (10.Net.Host.Host). Is the area 10.0.0.0/16 still private? Example: 10.0.0.1 is my router 10.0.0.2 a client/host. 10.0.1.x is…
Hello folks, I'm writing an exam soon on IPv6 subnetting. I've understood the topic so far, but the problem is that the teacher requires us to calculate 8,000 or more subnets. But here's my problem: The task will be as follows: Opposite: Prefix FD00:1:1:C000::/51 Total: The 8000th network Total: 1 network: '' 2 Network: ''…
192.168.0.0 – 192.168.63.63 192,168,64,64 – 192,168,127,127 192,168,128,128 – 192,168,191,191 192,168,192,192 – 192,168,255,255 Is my solution correct?
I don't understand the task below. What's the solution, and how did you come up with it? So, with a maximum of 350 hosts and as many additional subnets as possible… Task B: In a company, the network 172.20.0.0/16 is available. The network is to be divided into 6 subnets. The following must be observed:…
Hello everyone, I'm currently struggling with subnetting. I've managed to divide the subnet into four, but I have no idea how to include the hosts. Even with the solution, I can't figure out the calculation… Can someone explain this to me? Task: I'm supposed to divide the subnet 172.16.102.0/24 into four subnets. However, I'm supposed…