How do I calculate the antiderivative of sin(pi/2x)?
I thought now it is f(x) = sin(pi/2x) then be F(x) = cos(pi/2x) * 1/pi/2 F(x) = 2/pi * cos(pi/2x)
I thought now it is f(x) = sin(pi/2x) then be F(x) = cos(pi/2x) * 1/pi/2 F(x) = 2/pi * cos(pi/2x)
Hello, can someone explain to me step by step how to get the derivative of c, i.e. the second part where it says => G'(x)=β¦ Thank you for your answers ππΌππΌππΌ