Sudoku expert?
Hello,
Do you know how I can move forward? I'm kind of stuck here.😭
Thanks in advance! 🙂
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Let’s look at the (only two) possibilities for 8 in Box 9:
If r7c9 is an 8, r7c8 becomes a 6. At the same time, r4c7 and r6c7 will become a 5/8 pair (the 5 you already have and the 8 can now no longer be at any other point in c7 except in box 6). As a result, however, r4c8 would become a 6 and this is not due to the 6 in r7c8.
Therefore, r7c9 cannot be 8 and thus the 8 in box 9 in r8c7.
I’m sure you’ll be on your own.
I would never have seen many thanks!! I hope soon I can do this alone😭💪
In cell(8,7), 1,2,8,9 are approved
In cell(9,7) 1,2,6.9 are approved
In cell(9,8), 1,2,6.9 are approved
Now you have already discovered a “5.6” pair in the cells (9,4) and (9,6).
Thus, the “6”s fall into the cells (9,7) and (9.9).
A “1,2,9” triplet thus forms in the cells (8,7), (9,7) and (9.9).
Thus, the “1” in the cell (7,8) is no longer available. It is thus established that cell(7,8) can only be a “6”
In cell(9,8), 1,2,6.9 are approved
you have been hacked 🙂 (9.9) has been disfigured to (9,8)!
The “3” is already confirmed for the cell(9,8).
That’s not true! it’s not a triplet because in the cell 7,8 and 7.9 can stand 1
I know: but in your answer you write that in (9,8) 1 2 6 9 are allowed. You mean (9.9)