Subnetting -> VSLM task?
The provider assigns the address 178.0.0.0/16.
The following is required in the company:
• 3 subnets with 16200 computers are to be addressed.
• 7 subnets with 2000 computers are required.
• Two subnets with 1000 computers are to be created.
Here is the solution image.
I understand the number, for example /18 in the first column because 16200 <= 2^14, and 32 -14 = 18
but how do I get the jumps within the IP?
Here's the range depending on the bits, according to a YouTube video, but in my case it doesn't seem to work? 😛
(1 votes)
Loading...
Dumbly written, you just count up. If you divide the /16 into 4 parts, i.e. the 65536 addresses in 4 /18 a 16384 addresses, this is the first address of the next block. So the first block starts with the first address of your block 178.0.0.0/16 a, which is logically 178.0.0.0, the next then at 178.0.64.0, the next then at 178.0.128.0 and the last with 178.0.192.0. So these are simply always the address spaces with 16384 running IPs.
And for the next 2 steps you only share the remaining /18 in 8 /21 and then at the end the /21 in 2 /22.
Can you explain to me the use of invoices?
There’s not much to be expected. You just need to know where to split the net. With a /16 you can change the last 16bit, so the last 2 blocks are yours. So you can change everything after 178.0. 256 by 4 is 64. So the 4 /18 178.0.0.0, 178.0.64.0, 178.0.128.0 and 178.0.192.0 are.
which bills are broken everywhere in the answer
178.0.0.0/16 is a block as you juice, I quote The provider will assign the address 178.0.0.0/16. so correctly did not really understand that takes time, a block is a network and the block size is determined by the host component, the smaller the prefixes the larger the block da host component larger
7 months later, the homework is probably not quite up to date.
What I don’t understand
There’s no break in the answer. This is simply the notation for networks.
If you have an IP address with a subnet mask AND link, you will get the network ID. 1 AND 1 = 1, 0 AND 1 = 0, 1 AND 0 = 0
If you connect the IP address with the inverted subnet mask OR you get the broadcast IP:
1 OR 1 = 1, 1 OR 0 = 1, 0 OR 1 = 1
you need to have this bit pattern internalized, otherwise you don’t really understand what happens. exercise
178.0.192.0 with you as 18 and 21 prefixes, do not go where the packages should be pure 18 or 21 prefixes
3 subnets x 16200 with18 prefixes, ok, the other 7 subnets with 2000 computers in the 178.0.192.64 with 21 prefixes
http://w3service.net/ccna_certification/INFOs/sem2/SubnettingAndVLSM-014.pdf well explained