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It’s a bit here with me. R2 and R3 (parallel circuit) can be seen as a common resistance. There’s a formula for that. I come to 1/Rges = 1/R1 + 1/R2 => 40 Ohm
For the total resistance then to 140 ohms.
Total current 10 V / 140 Ohm = 0.0714A
In the parallel circuit, the current is then divided up in the size ratio of the resistors. The total current must pass through R1.
If you know the currents, you can calculate the voltages according to the ohmic law.
First of all, you need the replacement resistance R23 the parallel connection
of R2 and R3 Determine:
Now you calculate the total resistance:
With the total resistance RSECTION the total current I1 determined:
The voltage U1 to R1 Calculate:
The differential voltage U is applied to the parallel circuit23 to:
And with the voltage U23 the partial flows I2 and I3 at the resistors R2 and R3 Calculate:
Get the resistors together.
First of all, parallels Resistances R2 and R3 to R23 = R2*R3/(R2+R3)
R23 is then in Series with R1. So add to total.
With U = R * I you can now determine the total current.
With the same formula, you can now determine which voltage drops to R1, since the total current must also flow through R1.
The result allows you to determine which voltage drops to R2 and R3. Almost total – U1. The resistors are parallel, so the same voltage drops at both.
And with the result (and the formula already mentioned), you can also calculate the currents through R2 and R3.
What would the results be at I1?