Current in a resistor?
Hi, I've been given this assignment in preparation for my final exams this year. I'm supposed to calculate the current in the resistor when the switch is open. Generally speaking, this would be a series circuit, and the voltage would be split between the lamp and the resistor. I've already tried calculating everything and have come to the conclusion that the lamp should have a voltage between 3.05 and 3.85. But how do I get the exact voltage? So far, I haven't found any regularity that the values in the table follow, and therefore I can't calculate any values for the voltage between 3.05 and 3.85.
Maybe I'm missing something. I'd really appreciate some help.
(1 votes)
Loading...
hmm, OK…something misunderstood…
In any case, there are millimetres not an exact solution, since it lies between two pairs of values. So you have to interpolate! Either linear, or you use the regression function in the calculator!
I have now taken some examples – it doesn’t make any sense!
When at the incandescent lamp the voltage UL the difference UR the resistance R off. But you calculate the current I at constant resistance R is not the same as the specified current IL identical.
Also, no voltage can be applied to the lamp UL = 6.0 V drop if the resistance R in series and the power supply only U = 6.0 V.
Only answer to the question(s):
This task is not detachable!
So not only did I come to the conclusion. Thank you
The task can be easily solved graphically on cardboard paper:
At the intersection, the same current flows through the resistance and into the bulb (about 310 mA).