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merkurus
1 year ago

Aufgabe 3
(ZD + DE) / ZD = (ZA + AB) / ZA
(12 + 10) / 12 = (9 + AB) / 9
(12 + 10) / 12 * 9 = 9 + AB
((12 + 10) / 12 * 9) – 9 = AB
(22 / 12 * 9) – 9 = AB
16,5 – 9 = AB
AB = 7,5

AD / ZA = BE / (ZA + AB)
AD / 9 = 11 / (9 + 7,5)
AD = 11 / (9 + 7,5) * 9
AD = 11 / 16,5 * 9
AD = 6

(ZD + DE + EF) / (ZD + DE) = CF / BE
(12 + 10 + EF) / (12 + 10) = 15 / 11
(22 + EF) / 22 = 15 / 11
22 + EF = 15 / 11 * 22
EF = (15 / 11 * 22) – 22
EF = 30 – 22
EF = 8

Halbrecht
1 year ago

beachte , dass du ZE auch hast.